Mysql中group by子句结合count效率问题

  • A+
所属分类:Linux

今天碰到一个问题,如下一个表linuxeye的两列id、status,现在要统计数据格式如下,Google找到2种方法,引出Mysql中Group by子句结合count使用的效率问题

mysql>> select id,status from linuxeye;
+-----------+--------+
| id | status |
+-----------+--------+
|         4 | R      |
|         1 | R      |
|         2 | R      |
|         2 | S      |
|         5 | R      |
|         5 | C      |
|         3 | R      |
|         5 | C      |
|         5 | R      |
|         3 | R      |
|         3 | O     |
....
+-----------+----------+----------+----------+----------+
| id | status_O | status_S | status_C | status_R |
+-----------+----------+----------+----------+----------+
|         1 |        0 |        1 |        1 |        2 |
|         2 |        0 |        1 |        0 |        2 |
|         3 |        0 |        0 |        1 |        3 |
|         4 |        0 |        0 |        0 |        2 |
...

select id, \
(select count(*) from linuxeye where id=other.id and status='O') as status_O,\
(select count(*) from linuxeye where id=other.id and status='S' ) as status_S,\
(select count(*) from linuxeye where id=other.id and status='C' ) as status_C,\
(select count(*) from linuxeye where id=other.id and status='R'  ) as status_R \
from linuxeye as other group by id;

此方法中,group by子句在扫描表的时候,每一篇文章的都去执行了两次count,因此效率极低

select id,\
sum(case when status='O'  then 1 else 0 end) as status_O, \
sum(case when status='S'   then 1 else 0 end) as status_S, \
sum(case when status='C'   then 1 else 0 end) as status_C, \
sum(case when status='R'   then 1 else 0 end) as status_R \
from linuxeye group by id;

此方法,总共只需要执行一次表扫描,并且没有每次都count一下,而是用sum求一个总和,大大了减少了查询时间。效率会提高几百甚至几千倍

Sun Jan  6 14:58:59 CST 2013

avatar

发表评论

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen: